以么正轉換解決多載波調變通信系統中高峰均比問題的方法
刊登日期:2014/05/21
  ‧ 專利名稱 以么正轉換解決多載波調變通信系統中高峰均比問題的方法
  ‧ 專利證書號 I359584
8027398B2
  ‧ 專利權人 國立臺灣大學
  ‧ 專利國家
    (申請日)
中華民國 (2007/12/10)
美國 (2008/06/19)
 
  ‧ 發明人/PI 林茂昭 ,鄧尚康 ,陳添輝 ,羅于洪 ,
  ‧ 單位 電機工程學系
  ‧ 簡歷/Experience
技術摘要 / Our Technology:
本發明所提出的方法共包含下列步驟,首先對具有N個子載波之多載波調變通訊系統的基頻訊號區塊 ,j=1,2,…,B,先行補零,再透過LN點的反快速傅立葉變換以得到L倍的超取樣的時域訊號區塊 ,j=1,2,…,B。接下來,將 經過Q種不同的時域循環位移處理或頻域循環位移處理得到共Q個訊號區塊, ,ij=1,…,Q。然後,對  ,i2=1,…,Q,…,iB=1,…,Q,以BxB的么正矩陣U進行轉換。對於每一(i2,...,iB)組合,可得到一含B個時域訊號區塊的組合 ,c為任意常數。最後綜合比較QB-1種訊號區塊的組合,從其中挑選某一組合,其峰值最小者、峰均比最小者、或是剪除雜訊功率最小者傳送。

The method contains the following steps. First, in a MCM system with N sub-carriers, the baseband signal blocks Xj , j=1, 2, . . . ,B are supplemented with zeros and processed with LN-point IFFT, respectively, to obtain L-time oversampled time-domain signal blocks xj , j=1,2, . . . ,B. Then, xj undergoes Q Time Domain Circular Shifts or Frequency Domain Circular Shifts to obtain Q signal blocks {tilde over (x)}j (i j ), ij=1, Λ, Q. Subsequently, a B×B unitary transform is performed against ( x 1, {tilde over (x)}2 (i 2 ), . . . , {tilde over (x)}B (i B )). After the unitary transform, for each (i2, . . . , iB) a combination having B time-domain signal blocks is obtained as follows: ({tilde over (y)}1 (i 2 , . . . , i B ), {tilde over (y)}2 (i 2 , . . . , i B ), . . . , {tilde over (y)}B (i 2 , . . . ,i B ))=( x 1, {tilde over (x)}2 (i 2 ), . . . , {tilde over (x)}B (i B )) cU where U is the B×B unitary matrix, and c is an arbitrary constant (c≠0). Finally, the total QB−1 combinations are compared against each other to select a best candidate for transmission that could produce the lowest peak value, or the smallest PAPR, or the lowest clipping noise power.




專利簡述 / Intellectual Properties:




 

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